How to extract a value from a string using regex and a shell? -

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i in shell , have string: 12 bbq ,45 rofl, 89 lol

using regexp: \d+ (?=rofl), want 45 result.

is correct use regex extract data string? best have done highlight value in of online regex editor. of time remove value string.

i investigating expr, syntax errors.

how can manage extract 45 in shell script?

you can gnu grep's perl mode:

echo "12 bbq ,45 rofl, 89 lol"|grep -p '\d+ (?=rofl)' -o

-p means perl-style, , -o means match only.


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