iphone - i want to call an image to be displayed in a view -

hi wanted display randomly selected images in view. below example of code using generate random numbers displayed in lable. ( around way code , im aware there more concise approach code this. im doing way particular reason wont go now). wish replace the code in each case have code calls image displayed in view

nsstring *title = nil; nsstring *path = nil;  int number = arc4random() % 12; switch(number) { case 0: namel.text = @"1";              break;   case 1:             namel.text = @"2";      break;  case 2:             namel.text = @"3";              break;  case 3:             namel.text = @"4";              break;  case 4:             namel.text = @"5";              break; case 5:     namel.text = @"6";      break;  case 6:     namel.text = @"7";      break;  case 7:     namel.text = @"8";      break;  case 8:     namel.text = @"9";      break;    case 9:     namel.text = @"10";      break;  case 10:     namel.text = @"11";      break;  case 11:     namel.text = @"12";      break;                       break;             default:             break; } } @end 

you have use uiimageview. need array of image name. when random number, index in array , call imageview.image = [uiimage imagedname:[array objectatindex:randomindex]];