javascript - I need to match strings that don't contain a keyword at an arbitrary position -

i need match strings don't contain keyword (beta2) @ arbitrary position.

consider:

var astr    = [                 '/beta1/foo',                 'beta1/foo',                 '/beta1_xyz/foo',                 'blahblah/beta1/foo',                 'beta1',                  '/beta2/foo',                 'beta2/foo',                 '/beta2_xyz/foo',                 'blahblah/beta2/foo',                 'beta2',                  '/beat2/foo',                 'beat2/foo',                 '/beat2_xyz/foo',                 'blahblah/beat2/foo',                 'beat2'             ];  function btestformatch (str) {     return /.*\b(?!beta2).*/i.test (str); }  (var j=0, ilen=astr.length;  j < ilen;  j++) {     console.log (j, btestformatch (astr[j]), astr[j]); } 

we need regex matches strings exclude beta2. beta2 start @ word boundary, not end @ one. can @ variety of positions in string.

the desired results be:

 0    true    /beta1/foo  1    true    beta1/foo  2    true    /beta1_xyz/foo  3    true    blahblah/beta1/foo  4    true    beta1  5    false   /beta2/foo  6    false   beta2/foo  7    false   /beta2_xyz/foo  8    false   blahblah/beta2/foo  9    false   beta2 10    true    /beat2/foo 11    true    beat2/foo 12    true    /beat2_xyz/foo 13    true    blahblah/beat2/foo 14    true    beat2 

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the regex 3rd-party analysis tool takes javascript regular expressions filter sub-results. tool takes single line of regex. there no api , don't have access source-code.

is there javascript regex filter second beta results (beta2) analysis run?

try

/^(?!.*beta2).*$/