perl + identify if param is empty value from ARG -

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when run following script.pl script no arguments:

./script.pl

i not message no arg. why? how identify if $param null value or empty value, same [ -z ksh?

#!/usr/bin/perl $param = $argv[0]; if ($param = "") {     print no arg; } else {     print arg: $param; }

because it's not perl. did learn syntax? wrong it.

  1. $param = "" assigns empty string $param, that's not want.

  2. null spelled undef in perl.

  3. to compare strings, use eq operator.

  4. you must quote strings: print "no arg"

much easier:

#!/usr/bin/perl if (@argv) {     print 'have parameters'; } else {     print q{don't have parameters}; }

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