jquery next by class fade out -

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<div id="formheadtop">  <input class="checkbox" type="checkbox" /></div><div class="formbody"></div> <div id="formheadtop"> <input class="checkbox" type="checkbox" /></div><div class="formbody"></div> <div id="formheadtop"><input class="checkbox" type="checkbox" /></div><div class="formbody"></div>    $(function() { $('input:checkbox').live('click', function () { if ( $(this).attr('checked') == true )  {     $(this).nextall('.formbody:first').fadein(); } else {  $('.formbody').fadeout(); }; });

the code doesn't work. want fade out next div.formbody.

first we'll need change id="formheadtop" class="formheadtop", since ids must unique. can use code fade in , out divs:

jquery

$(document).ready(function(){   $('.formheadtop :checkbox').live('click', function() {     if ($(this).is(':checked')) {       $(this).parent().next('.formbody').fadein();     }  else {        $(this).parent().next('.formbody').fadeout();     };   }); });

you shorten $(this).parent().next('.formbody') $(this).parent().next().fadein(), put in selector, in case ever want put in between.

html

<div class="formheadtop"><input class="checkbox" type="checkbox" checked="checked" /></div> <div class="formbody">test</div> <div class="formheadtop"><input class="checkbox" type="checkbox" checked="checked" /></div> <div class="formbody">test</div> <div class="formheadtop"><input class="checkbox" type="checkbox" checked="checked" /></div> <div class="formbody">test</div>

i made checkboxes checked default. if not, you'll need hide content in formbody tags.

here's code in action.


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